A sea lion swims in still water at a speed …

Mathematics Questions

A sea lion swims in still water at the speed of 15 km/h. While hunting for fish, it swims with the current for 35 km and against the same current for 25 km. The sea lion swims with the current for the same amount of time it swims against the current. What is the speed of the current?

Short Answer

The problem involves defining the current’s speed (x) and the sea lion’s modified speeds while moving with and against the current. By setting the times for both scenarios equal and solving the resulting equation, we find that the speed of the current is 2.5 km/hr.

Step-by-Step Solution

Step 1: Define the Variables

To solve the problem, we start by defining the variables involved. Let x be the speed of the current in km/hr. The sea lion’s speed when moving with the current becomes 15 + x, while moving against the current, it becomes 15 – x. These adjustments account for the influence of the current on the sea lion’s natural speed.

Step 2: Establish the Equations

Next, we establish the equations based on the information given. The total distance traveled with the current is 35 km, and against the current is 25 km. The times taken for both scenarios can be represented as follows:

  • Time with the current: 35/(15 + x)
  • Time against the current: 25/(15 – x)

Setting these two expressions equal allows us to create one equation to solve for x.

Step 3: Solve the Equation

Now, we can solve the equation derived from equating the two time expressions. The equation can be simplified to:

  • 35/(15 + x) = 25/(15 – x)
  • Cross-multiplying gives us: 150 – 60x = 0

After simplifying, we find x = 2.5 km/hr, indicating the speed of the current. This concludes the problem-solving process.

Related Concepts

Variable

A symbol or letter used to represent an unknown value in mathematical expressions or equations

Equation

A mathematical statement that asserts the equality of two expressions, containing one or more variables

Cross-Multiplication

A technique used to solve proportions by multiplying the numerator of one fraction by the denominator of the other fraction, allowing for the simplification of equations.

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